Question

{[(2A-2B)/(a^2-2AB+B^2)]+B/(A^2-B^2)}÷(3b+2a)/(a+b)

Answer 1

原式

=[2(a-b)/(a-b)²+b/(a+b)(a-b)]×(a+b)/(2a+3b)

=[2/(a-b)+b/(a+b)(a-b)]×(a+b)/(2a+3b)

=[2(a+b)+b]/(a+b)(a-b) ×(a+b)/(2a+3b)

=(2a+3b)/(a-b) ×1/(2a+3b)

=1/(a-b)