Question

如图,∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.试说明：∠ADE=∠AED.

Answer 1

1）因为、∠BAC=∠DAE,所以∠BAC-∠DAF=∠DAE-∠DAF,→∠BAD=∠CAE;

2)因为∠BAD=∠CAE,∠ABD=∠ACE,BD=CE,所以△ABD=△ACE;

3)因为△ABD=△ACE,所以AD=AE;

4)在△ADE中,有AD=AE,所以△ADE为等腰三角形,所以∠ADE=∠AED

得证!