(x^2-x)^2-18(x^2-x)+72

2个回答

  • (x^2-x)^2-18(x^2-x)+72

    =(x^2-x-6)(x^2-x-12)

    =(x-3)(x+2)(x-4)(x+3)

    (x+1)(x+2)-x-10

    =x^2+3x+2-x-10

    =x^2+2x-8

    =(x+4)(x-2)