=[2/(a+2)(a-2)][(a²-4a+4)/4a]/[(a-2)/2a]
=[2/(a+2)(a-2)][(a-2)²/4a][2a/(a-2)]
=4a(a-2)²/[4a(a+2)(a-2)²]
=1/(a+2)
=1/(1/2+2)
=2/5
=[2/(a+2)(a-2)][(a²-4a+4)/4a]/[(a-2)/2a]
=[2/(a+2)(a-2)][(a-2)²/4a][2a/(a-2)]
=4a(a-2)²/[4a(a+2)(a-2)²]
=1/(a+2)
=1/(1/2+2)
=2/5