Lim(x→1) (x2-4x-5 )/(x2-1)求极值
1个回答
Lim(x→1) (x2-4x-5 )/(x2-1)
=lim (x+1)(x-5)/[(x+1)(x-1)]
=lim(x-5)/(x-1)
=∞
相关问题
lim(x→4)x^2-2x-8/x^2-16 求函数极值,
求极值x→∞ lim(3+x)/(x+2)^ 2x
lim(x→0+)xln2x 求函数极值,
1.5求极限lim(x→4) (x^2-6x+8)/ (x^2-5x+4)
y=2x+4/x 求极值~y=2x+4/x 求极值
lim(x→∞)[(X^2+2x+5)/(4x^2-x+1) =(1+2/x+5/x^2)/(4-1/x+1/x^2)=
求极根lim(x→2) x^2-5x+6/x^2+2x-8
求y=1/(x^2-2x+4)的极值
lim(x^2-1)/(x^2-5x+4) x趋向于2 求极限
求lim 的极限1.lim h →0 {[1/(5+h)]-1/5}/h2.lim x→1 (x^3-x^2+2x-2)