6y-(y+2分之y+2-y分之y)÷(y^3-4

6y-(y+2分之y+2-y分之y)÷(y^3-4y-2y^2+8分之y) 怎么算

1个回答

=6y -[y/(y+2)-y/(y-2)]÷y/[(y³-2y²)-(4y-8)]
=6y-y(y-2-y-2)/(y+2)(y-2)×(y-2)²(y+2)
=6y+4(y-2)
=10y-8