数学计算题,八年级上(1)(5a+6b-7c)^2-(5a-6b+7c)^2 (2)(2x-3y-1)(2x+3y+1)

2个回答

  • (1)(5a+6b-7c)^2-(5a-6b+7c)^2=【(5a+6b-7c)+(5a-6b+7c)】×【(5a+6b-7c)-(5a-6b+7c)】

    =10a(12b-14c)=120ab-140ac

    (2)(2x-3y-1)(2x+3y+1)=【2x-(3y+1)】×【2x+(3y+1)】=4x^2-(3y+1)^2=4x^2-9y^2-6y-1

    (3)没看懂,另请高人吧!

    (4)已知x^m=9,x^n=6.x^k=4求x^m-2n-2k

    解x^(m-2n+2k)=x^m/(x^n)^2*(x^k)^2=9/36*16=4

    (5)a^a-3=1 a^a-3×a^3=1×a^3 所以a^a=a^3 所以a=3

    (6)你不小心打错数了吧,7x应为7x^2:若3x^2-x=1,求6x^3+7x^2-5x+2009

    因为3x^2-x=1,所以3x^2=x+1

    所以6x^3+7x^2-5x+2009

    =x(6x^2+7x-5)+2009

    =x(2x-1)(3x+5)+2009

    =(2x-1)(3x^2+5x)+2009

    =(2x-1)(1+x+5x)+2009

    =(2x-1)(6x+1)+2009

    =12x^2-4x-1+2009

    =4(3x^2-x)+2008

    =4*1+2008

    =2012