Question

HELP~,椭圆题.求经过点(-3/2,5/2)与(√3,√5)两点的椭圆的标准方程.

Answer 1

x^2/a^2+y^2/b^2=1

把(-3/2,5/2)与(√3,√5)代入

9/(4a^2)+25/(4b^2)=1

所以9/a^2+25/b^2=4 (1)

3/a^2+5/b^2=1 (2)

(1)-(2)*5

-6/a^2=-1

a^2=6,b^2=10

x^2/6+y^2/10=1