pH=2即c(H+)=0.01mol/L
pH=4即c(H+)=0.0001mol/L
设体积分别为2V和3V
则混合后n(H+)=0.01*2V+0.0001*3V=0.0203V
c(H+)=0.0203V/(2V+3V)=0.00406mol/L
pH=2.4
pH=2即c(H+)=0.01mol/L
pH=4即c(H+)=0.0001mol/L
设体积分别为2V和3V
则混合后n(H+)=0.01*2V+0.0001*3V=0.0203V
c(H+)=0.0203V/(2V+3V)=0.00406mol/L
pH=2.4