[-(2x-y)²-(x+2y)(x-2y)-1/3(x+3y)²]÷(-2/3x)
=[-(4x^2-4xy+y^2)-(x^2-4y^2)-1/3(x^2+6yx+9y^2)/(-2/3x)
=[-4x^2+4xy-y^2-x^2+4y^2-x^2/3-2xy-3y^2)/(-2/3x)
=[-16/3x^2+2xy]/(-2/3x)
=8x-3y
[-(2x-y)²-(x+2y)(x-2y)-1/3(x+3y)²]÷(-2/3x)
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