Question

一道初二平行四边形几何题,平行四边形ABCD,AE垂直于BC,AF垂直于CD,角EAF为45度,AE加AF等于2倍根号2

Answer 1

∠BCD=360°-45°-90°-90°=135°

∠ABC=∠CDA=45°

AB=√2AE

AD=√2AF

AB+AD=√2(AE+AF)=√2×2√2=4

平行四边形的周长=2(AB+AD)=2×4=8