x³-3x²+2=0x³-x²-(2x²-2)=0x²(x-1)-2(x+1)(x-1)=0(x-1)(x²-2x-2)=0x-1=0 或x²-2x-2=0x=1或x²-2x+1=3(x-1)²=3x-1=±√3于是x1=1+√3 x2=1-√3 x3=1
x³-3x²+2=0x³-x²-(2x²-2)=0x²(x-1)-2(x+1)(x-1)=0(x-1)(x²-2x-2)=0x-1=0 或x²-2x-2=0x=1或x²-2x+1=3(x-1)²=3x-1=±√3于是x1=1+√3 x2=1-√3 x3=1