Question

方程组(x+y)/3+(x-y)/2=3,(x+y)/3-(x-y)/2=-1的过程,规范

Answer 1

(x+y)/3+(x-y)/2=3 (1) 去分母得 2(x+y)+3(x-y)=18,简化得 5x-y=18 (3)

(x+y)/3-(x-y)/2=-1 (2) 去分母得 2(x+y)-3(x-y)=-6,简化得 5y-x=-6 (4)

由(4)得 x=5y+6,代入(3),y=-0.5

将y=-0.5代入(4),得 x=3.5

所以方程组的解是：x=3.5,y=-0.5