du/dx =F(G(X)+Y)'*(G(X)'+Y')
由y^2=SIN(X+Y),得 2ydy=cos(x+y)*(dx+dy)
所以 dy/dx=cos(x+y)/[2y-cos(x+y)]
所以du/dx =F(G(X)+Y)'*(G(X)'+cos(x+y)/[2y-cos(x+y)])
du/dx =F(G(X)+Y)'*(G(X)'+Y')
由y^2=SIN(X+Y),得 2ydy=cos(x+y)*(dx+dy)
所以 dy/dx=cos(x+y)/[2y-cos(x+y)]
所以du/dx =F(G(X)+Y)'*(G(X)'+cos(x+y)/[2y-cos(x+y)])