Question

lim n→∞ ( n 2 +1 n+1 -an-b)=0 ，则a=______，b=______．

Answer 1

∵

lim

n→∞ (

n 2 +1-a n 2 -bn-an-b

n+1 ) =

lim

n→∞ (

(1-a) n 2 -(b+a)n+1-b

n+1 )=0 ，

∴1-a=0，a+b=0

∴a=1，b=-1

故答案为 1；-1