Question

高一函数解析式求法f(x+1)=x方-3x+2

Answer 1

f(x+1)=x方-3x+2

换元法,设x+1=t ,则有 x =t-1 ,

则 f(x+1)=f(t)=x方-3x+2=(t-1)^2-3(t-1)+2 展开得

f(t) = t^2-2t+1-3t+3+2

= t^2-5t+6