1.已知tanX=2,求:(tan2X—tanX)/(1+tan2X tanX)的值.

2个回答

  • (tan2X—tanX)/(1+tan2X tanX)

    =tan(2X—X)

    =tanX

    =2

    sin(X—Y)cosY+cos(X—Y)sinY

    =sin(X—Y+Y)

    =sinX

    cos80°sin50°—sin40°sin80°

    =cos80°(sin90°-40°)—sin40°sin80°

    =cos80°cos40°—sin80°sin40°

    =cos(80°+40°)

    =cos120°

    =-1/2

    X,Y为锐角,且sinX=(12/13),sinY=(3/5)

    cosX=5/13,cosY=4/5

    sin(X+Y)

    =sinXcosY+cosXsinY

    =12/13*4/5+5/13*3/5

    =48/65+15/65

    =63/65

    sin15°cos15°

    =1/2sin30°

    =1/2*1/2

    =1/4

    2(cos^2 )* (π/8) —1

    =cos(2*π/8)

    =cos(2*π/8)

    =cosπ/4

    =√2/2

    cosX=(1/5),(3π/2)