Question

求导(1)y=(1-根号x)(1+1/根号x)

Answer 1

y=(1-根号x)(1+1/根号x)

y=(1-√x)(1+1/√x)

y=(1-√x)(√x+1)/√x

y=(1-x)/√x

y'=[-√x+(1-x)/(2√x)]/x

y'=(-2x+1-x)/(2x√x)

y'=(1-3x)/(2x√x)

y'=(1-3x)√x/(2x^2)