Question

先化简再求值：-10(-a^3b^2c)^2×五分之一a×(bc）^3-(2abc)^3×（-a^2b^2c)^,其中a

Answer 1

-10(-a^3b^2c)^2×五分之一a×(bc）^3-(2abc)^3×（-a^2b^2c)^2

=-10a^6b^4c^2×1/5a×b^3c^3-8a^3b^3c^3×a^4b^4c^2

=-2a^7b^7c^5-8a^7b^7c^5

=-10a^7b^7c^5

=-10(ab)^7c^5

=-10*(-1)*32

=320