两个电阻串联 则电路总电阻
R=R1+R2=nR2+R2=(1+n)R2
则有
U1=(R1/R)U=(nR2/(1+n)R2))U=(n/(1+n))U
U2=(R2/R)U=(R2/(1+n)R2))U=(1/(1+n))U