化简根号3sin(π/6-a)-cos(π/6-a)
1个回答
根号3sin(π/6-a)-cos(π/6-a)
=2[sin(π/6-a)*cosπ/6-sinπ/6*cos(π/6-a)]
=2sin(π/6-a-π/6)
=2sin(-a)
=-2sina
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