求y=sin(x-π/4)cos(x+π/4),x

求y=sin(x-π/4)cos(x+π/4),x属于[0,π/4]的反函数

1个回答

y=sin(x-π/4)cos(x+π/4)=sin(x-π/4)sin(π/4-x)=-sin²(x-π/4)=(cos2x-1)/2
y=sin(x-π/4)cos(x+π/4),x属于[0,π/4]的反函数
f^-1(x)=[arccos(2x+1)]/2,x属于[-1/2,1/2]

求y=sin(x-π/4)cos(x+π/4）的反函数（1）x属于【-π/4,π/4】（2）x属于【π/4,π/2】
已知sin(π/4-x)=5/13,x属于(0,π/4),求(cos2x)/cos[(π/4)+x]
求证:sin(π/4+x)/sin(π/4-x)+cos(π/4+x)/(π/4-x)=2/cos2x
已知sin(π/4--x)=5/13,0
已知sin[(π/4)-x)]=5/13,0
sinx=-15/17 x属于(3π/2,2 π) 求sin(x+π/4) cos(π/4- x)的值
已知0＜x＜π/4,sin(π/4-x)=5/13,求(cos2x)/(cos(π/4+x))的值.
已知0＜x＜π/4,sin(π/4-x)=5/13,求cos2x/cos(π/4+x)的值
sin(x-π/4 + π/2 )=-cos(x+π/4)
cos(π/4-x)=3/5,sin(5π/4+y)=-12/13 当X在(π/4,3π/4)Y在(0,π/4)时求si