初二（上）整式问题若X+Y=1,则代数式x4(次方 - 知识问答

初二（上）整式问题若X+Y=1,则代数式x4(次方）+6x³y -2x²y+10x²y&s

2个回答

原式=(x^4-2x²y²+y^4)+(6x³y+12x²y²+6xy³)-(2x²y+2xy²)
=(x²-y²)²+6xy(x+y)²-2xy(x+y)
=(x+y)²(x-y)²+6xy×1²-2xy×1
=1²×(x-y)²+6xy-2xy
=x²-2xy+y²+4xy
=x²+2xy+y²
=(x+y)²
=1²
=1

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