过程在这儿了,
(1)1 2 2 22 1 2 22 2 1 22 2 2 1(2)1 2 3 42 1 0 03 0 1 04 0 0
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观察下列算式:12-02=1+0=1;22-12=2+1=3;32-22=3+2=5;42-32=4+3=7;52-42
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观察下列算式:12-02=1+0=1;22-12=2+1=3;32-22=3+2=5;42-32=4+3=7;52-42
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观察下列算式:12-02=1+0=1;22-12=2+1=3;32-22=3+2=5;42-32=4+3=7;52-42
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计算行列式的值 D=1 1 0 -22 0 -1 -10 0 2 1-1 2 1 0
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(2001•常州)(-2)0=11;(12)-1=22;11−2=-1-2-1-2.
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((0.4+1/3)*1又5/22-1.3*1/2)/0.15
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(0.1x-0.3)/0.03=(2x+1)/0.2+1.2
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(0.01+0.04x/0.03)-(1-0.3x/0.2)=1
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x-4/1x=8/3 x-0.8x=22.3/2x+2/1x=42