若m=1/log5(19)+2/log3(19)+3/log2(19),n=1/log2(π)+1/log5(π),则m
1个回答
m=log19(5)+2log19(3)+3log19(2)=log19(5×9×80)=log19(360)
2,所以m
1年前
3
相关问题
若3/log2 19+2/log3 19+1/log5 19=log19 m,求m的值
已知log2[log1/2(log2x)]=log3[log1/3(log3y)]=log5[log1/5(log5z)
[1log1/4]19+[1log1/5]13等于( )
求证:log2(π)+log5(π)>2
求值:3^(log3 (25) )+(-C(5,4)^(log2 1)+16^(log4(2sin(π/2))=
计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
若log2 3×log3 6×log6 m=log3 27,则m=
求等式log(2)3*log(3)4*log(4)5*log(5)6*log(6)7*log(7)m=log(3)9时m
已知log3 m=-1/log2 3,则m=
已知2^m=3 log2 5=n,则log15 2=