因为:
x(x+1)(x+2)(x+3)
=x(x+3)(x+1)(x+2)
=(x²+3x)(x²+3x+2)
而因为
x = (√5 - 3) / 2
代入
x²+3x
得
x² + 3x = [ (√5 - 3) / 2 ]² + 3 × [ (√5 - 3) / 2 ] = -1
代入上式
即
x(x+1)(x+2)(x+3)
=(x²+3x)(x²+3x+2) = (-1)× (-1 + 2) =(-1)× (1) = -1
不明白HI
因为:
x(x+1)(x+2)(x+3)
=x(x+3)(x+1)(x+2)
=(x²+3x)(x²+3x+2)
而因为
x = (√5 - 3) / 2
代入
x²+3x
得
x² + 3x = [ (√5 - 3) / 2 ]² + 3 × [ (√5 - 3) / 2 ] = -1
代入上式
即
x(x+1)(x+2)(x+3)
=(x²+3x)(x²+3x+2) = (-1)× (-1 + 2) =(-1)× (1) = -1
不明白HI