(x∧2-4x)∧2+16(x∧2-4x)+64
1个回答
=(x²-4x+8)²
若已解惑,请点右上角的
相关问题
2x+16=64 (2)2x-7点4=120 (3)
分解因式:①(a+b)^2+2(a+b)+1 ③4x^4-4x^3+x^2 ④x^2-16ax+64a^2 ⑤(x-1)
(4/X+2)+(16X^3/X^4-16)+(8X/X^2+4)+(4/X-2)
x^2+y^2=64 (8-x)^2+(y-4)^2=16 怎么解的?
(x-2)(x+2)(x^4+4x^2+16)
若x是根号16的算是平方根,求x^2(x^4+4x^2+16)-4(x^4+4x^2+16)
(2005•滨州)计算x4−16x4+8x2+16÷x2−x−2x2+4+x2+xx2+2x+1
(x^2-4x)(x^2-4x+8)+16
(x^2 + 4x)(x^2 + 4x+8)+16
(x-4x)^2+8(x^2-4x)+16