Question

(a-根号18)的平方+根号下b-5+C-根号8的绝对值=0 则A B C 能否构成三角形

Answer 1

[a-(18)^(1/2)]^2 + (b-5)^(1/2) + |c-8^(1/2)| = 0,

[a-(18)^(1/2)]^2 = (b-5)^(1/2) = |c-8^(1/2)| = 0,

a=(18)^(1/2) ,b = 5,c = 8^(1/2),

a+c=(18)^(1/2)+8^(1/2)=3*2^(1/2) + 2*2^(1/2) =5*2^(1/2) > 5*1=5=b.

a,b,c能构成三角形.