计算:1/1x2+1/2x3+1/3X4+...+1/9x10=?
1个回答
1/1x2+1/2x3+1/3X4+...+1/9x10
=1-1/2+1/2-1/3+1/3-1/4+……+1/9-1/10
=1-1/10
=9/10
相关问题
计算:1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+……+1/(x+9)(x+10)
-1/1x2-1/2x3-1/3x4-.-1/9x10
1/2x3+1/3x4+1/4x5.+1/9x10
计算(1)(3x+4)(3x-4) (2)(2x+1)(2x+3) (3)(9x+4y)(9x-4y)
计算:1 1 1 1 1 ——+ ——+——+.+————+———— 1x2 2x3 3x4 99x100 100x10
1/2X3=1/2-1/3 1/3X4=1/3-1/4请根据以上规律计算:1/2X3+1/3X4+1/4X5+.+1/9
(1-1/2)x(2-2/3)x(3-3/4)x……x(8-8/9)x(9-9/10)
计算:(1)[x−2/x+3•x2−9x2−4];(2)[3/x−4−24x2−16];(3)[1/2x−1x+y•(x
计算:2X(1/2X²-1)-3X(1/3X²+2/3)因式分解:4+12(x-y)+9(x-y)&
2x-1/3-10x-1/6-2x+1/4=1怎样计算?