Question

m为何实数时,方程7x^2-(m+13)x +m^2 -m-2=0的两根分别在区间（0,1)和（1,2）内?

Answer 1

令f(x)=7x^2-(m+13)x+m^2-m-2

有f（0）=m^2-m-2>0 且 f(1)= m^2-2m-80

可得 m>2或m