Question

a与b互为倒数,—c与d/2互为相反数,x的绝对值=3,求2ab-2c+d+x/3的值

Answer 1

a与b互为倒数.则a*b=1

—c与d/2互为相反数.则-c+d/2=0

-2c+d=0

x的绝对值=3,则X=3 或X=-3

2ab-2c+d+x/3

=2(a*b)+(-2c+d)+x/3

=2*1+0+x/3

=2+x/3 X等于正负3.所以2+x/3=2+3/3=3 或2+(-3/3)=1

2ab-2c+d+x/3的值为3或1