(1)∵3 2+4 2=25,2×3×4=24,
∴3 2+4 2,>2×3×4;
(2)∵2 2+2 2=8,2×2×2=8,
∴2 2+2 2=2×2×2;
(3)∵1 2+ (
3
4 ) 2 =
25
16 ,2×1×
3
4 =
3
2 ,
∴1 2+ (
3
4 ) 2 >2×1×
3
4 ;
(4)∵(-2) 2+5 2=29,2×(-2)×5-20,
∴(-2) 2+5 2>2×(-2)×5;
(5)∵ (
1
2 ) 2 +(
2
3 ) 2 =
25
36 , 2×
1
2 ×
2
3 =
2
3 =
24
36 ,
∴ (
1
2 ) 2 +(
2
3 ) 2 > 2×
1
2 ×
2
3 .
故答案为:>;=;>;>;>.
用字母表示为:a 2+b 2≥2ab(当a=b时等号成立).