2/(a+3) +3/(3-a) +(a+15)/(a²-9)
=2/(a+3)-3/(a-3)+(a+15)/[(a+3)(a-3)]
=[2(a-3)-3(a+3)+(a+15)]/[(a+3)(a-3)]
=(2a-6-3a-9+a+15)/[(a+3)(a-3)]
=0/[(a+3)(a-3)]
=0
2/(a+3) +3/(3-a) +(a+15)/(a²-9)
=2/(a+3)-3/(a-3)+(a+15)/[(a+3)(a-3)]
=[2(a-3)-3(a+3)+(a+15)]/[(a+3)(a-3)]
=(2a-6-3a-9+a+15)/[(a+3)(a-3)]
=0/[(a+3)(a-3)]
=0