siny+e^x=xy^2,两边求微分,cosydy+e^xdx=d(xy^2)
cosydy+e^xdx=y^2dx+2xydy
整理,得(e^x-y^2)dx=(2xy-cosy)dy
dy/dx=(e^x-y^2)/(2xy-cosy)
siny+e^x-xy^2=0,求dy/dx
1个回答
相关问题
-
设e^xy-xy^2=Siny,求dy/dx
-
设siny+ex(是e的x次方)-xy=0.求dy/dx
-
[e^x+f(x,y)]dx+(siny+xy)dy=0为恰当微分方程求f(x,y)
-
设函数y=y（x）是由方程xy+siny+x^2-√e=0所确定的隐函数，求dy/dx
-
求由siny+e-xy=e确定的隐函数y的倒数dy/dx
-
求导：xy=x-e^xy,求dy/dx
-
x^2y-e^2x=siny 求dy/dx 我的答案是：(x^2)y-e^2x-siny=0 对两边对x求导.得出 (2
-
∫(x^2-y)dx+(x+siny)dy
-
x-siny/x+tanx=0的导数dy/dx
-
设xy-e^xy=e 求dy/dx