[（x^2-6x+9）/(x+3)]÷[﹙x-3﹚/﹙x^2+6x+9﹚] = [（x-3）^2/(x+3)]÷[﹙x-3﹚/﹙x+3﹚^2] =(x-3)^2(x+3)^2/((x+3)(x-3)) =(x+3)(x-3)=x^2-9 因为x^2=3 所以原题=-6
若x=3/x,则[（x^2-6x+9）/(x+3)]÷[﹙x-3﹚/﹙x^2+6x+9﹚]=?
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