(1)75-(6,x)=15
75-(6^2+3x)=15
75-36-3x=15
3x=24
x=8
(2)根据已知n@3=n(n+1)(n+2)
则(n+1)/(n@3)=1/n(n+1)(n+2)
=1/n(n+2)=1/575
即n^2+2n-575=0
(n+25)(n-23)=0
n=-25(舍,因为n是自然数),n=23
则n=23
(1)75-(6,x)=15
75-(6^2+3x)=15
75-36-3x=15
3x=24
x=8
(2)根据已知n@3=n(n+1)(n+2)
则(n+1)/(n@3)=1/n(n+1)(n+2)
=1/n(n+2)=1/575
即n^2+2n-575=0
(n+25)(n-23)=0
n=-25(舍,因为n是自然数),n=23
则n=23