Question

计算题,我有急用,化简,(1)√8-√1／8(2)(√2+1)²-(√2-1)²方程(1)3(x-1)²=x-1(2)2

Answer 1

(1)√8-√1／8 =8/√8-1／√8=(8-1)/√8=7/√8=(7*√8)/8 (2)(√2+1)²-(√2-1)² =[(√2+1)+(√2-1)]*[(√2+1)-(√2-1)] =[2*√2]*2=4√2 (1)3(x-1)²=x-1 a. X=0 b. 3(x-1)=1; x=4/3 (2)2x²-x-6=0 (2x+3)*(x-2)=0 a. x=-3/2 b. x=2