原式=2(x-4)/(x+4)(x-4)+x/(x+4)
=2/(x+4)+x/(x+4)
=(x+2)/(x+4)
4/(xx-16)/2/x-4+x/x+4=?
2个回答
相关问题
-
化简：x2−16x2+8x+16+xx−4．
-
（2005•滨州）计算x4−16x4+8x2+16÷x2−x−2x2+4+x2+xx2+2x+1
-
(-xx+5+4x)+( 5x-4+2xx)其中x=-2
-
求方程组X1+X2+X3+4xX4-3xX5=02xX1+X2+3xX3+5xX4-5xX5=0X1-X2+3xX3-2
-
(4/X+2)+(16X^3/X^4-16)+(8X/X^2+4)+(4/X-2)
-
已知3xx-4x+6=o求xx-3x+4+2xx-x+8
-
怎样玩数独?1) x79,35x,4x8 3x4,821,79582x,4x7,x61x4x,1xx,xx6xx2,63
-
配方法 XX-4X+7和-XX+4X-4
-
计算(3xx−2−xx+2)•x2−4x=______．
-
29x54xxxx _第一题xxxxxxxxxxx39xxx6x6x9xx3x4xx4xx2xx7xx8x1xx5x2x