这个嘛
a1+2d+a1+4d=b4
2a1+6d=b4=b1*q^3
2+6d=q^3
b2*b3=b1*q^3=a8=a1+7d=2+6d
d=1
因为2+6=q^3,q=2
S10=10a1+45d=55
T10=b1(1-q^n)/(1-q)=-（1-2^10)=-1023
挺容易的
设｛an｝为等差数列,｛bn｝为等比数列,且a1=b1=1,a3+a5=b4,b2b3=a8
2个回答
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