应该是已知条件敲错了,少了一个t,应为I(t)=2sin【(2π/T)t-π/4】
所以当t=0时,有I(t)=2sin【(2π/T)*0-π/4】=2sin(0-π/4)=2sin(-π/4)=2*(-√2/2)=-√2
当t=T/8时,有I(t)=2sin【(2π/T)*T/8-π/4】=2sin(π/4-π/4)=2sin0=0
应该是已知条件敲错了,少了一个t,应为I(t)=2sin【(2π/T)t-π/4】
所以当t=0时,有I(t)=2sin【(2π/T)*0-π/4】=2sin(0-π/4)=2sin(-π/4)=2*(-√2/2)=-√2
当t=T/8时,有I(t)=2sin【(2π/T)*T/8-π/4】=2sin(π/4-π/4)=2sin0=0