Question

有这样一道题:"当a=3,b=-2/3时,求多项式7a^3-6a^3b+3a^2b+3a^3+6a^3b-3a^2b-1

Answer 1

原式=(7a^3+3a^3-10a^3)+(-6a^3b+6a^3b)+(3a^2b-3a^2b)-2

=0+0+0+2

=2

结果是2

所以他说得对