(x+1)(x+2)(x+3)(x+4)-(x^2+5x+3)(x^2+5x+7)
=(x+1)(x+4)(x+2)(x+3)-(x^2+5x+3)(x^2+5x+7)
=(x^2+5x+4)(x^2+5x+6)-((x^2+5x)+3)((x^2+5x)+7)
=(x^2+5x)^2+10(x^2+5x)+24-((x^2+5x)^2+10(x^2+5x)+21)
=(x^2+5x)^2+10(x^2+5x)+24-(x^2+5x)^2-10(x^2+5x)-21
=3
换算x^2==
(x+1)(x+2)(x+3)(x+4)-(x^2+5x+3)(x^2+5x+7)=?
5个回答
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