利用sin(a+b)=sin(a)cos(b)+cos(a)sin(b)
sin（x+π/3)=1/2sin(x)+（根号3）/2cos(x)
sin(x+2π/3)=-1/2sin(x)+(根号3）/2cos(x)
原式=3/2（sinx）^2+3/2cos(x)^2
化简：（sinx）^2+(sin（x+π/3))^2+(sin(x+2π/3))^2
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