x-(1/1-x)-(x^3-3x+1/x^2-1)
=x-(1/1-x)-{x(x^2-1)-2x+1}/x^2-1
=x+(1/x-1)-x+(2x-1)/x^2-1
=(2x-1)/x^2-1+(x+1)/(x+1)(x-1)
=(2x-1+x+1)/x^2-1
=3x/x^2-1
=(3x-1/3 )/(-1/3)^2-1
=-1/(-8/9)
=9/8
x-(1/1-x)-(x^3-3x+1/x^2-1)
=x-(1/1-x)-{x(x^2-1)-2x+1}/x^2-1
=x+(1/x-1)-x+(2x-1)/x^2-1
=(2x-1)/x^2-1+(x+1)/(x+1)(x-1)
=(2x-1+x+1)/x^2-1
=3x/x^2-1
=(3x-1/3 )/(-1/3)^2-1
=-1/(-8/9)
=9/8