Question

编程序计算1-1/2!+1/3!-1/4!+……+（-1）^(n-1)*1/n!,精确度为0.000001

Answer 1

#include#includevoid main() { int n=1; double temp=1.0,sum=1.0; do { n=n+1; temp=-temp/n; sum+=temp; } while (fabs(temp)>=1e-6); printf("sum=%fn",sum); }