Question

1.求y=(cos x)^2的微分.2.求y=sin(x^2-1)的微分.

Answer 1

1. d(cosx)^2=2cosx(-sinx)dx=-sin2xdx

2. dsin(x²-1)=cos(x²-1)d(x²-1)=cos(x²-1)×2xdx=2xcos(x²-1)dx