Question

1.已知x≠2y,x²-x=4y²-2y,求x+2y的值.

Answer 1

x²-4y²+(x+2y)=0

(x+2y)(x-2y)+(x+2y)=0

(x+2y)(x-2y+1)=0

x+2y=0

x-2y+1=0

x=-1/2

y=1/4