3x-2m+1=0,则x=(1-2m)/3
m=1-2x,则2x=1-m,则x=(1-m)/2
解互为相反数,则(1-2m)/3+(1-m)/2=0
两边同时乘以6,得
2(1-2m)+3(1-m)=0
2-4m+3-3m=0
7m=5
m=5/7