怎么最后一项的分子变了?先把题目写清楚
Sn=1/(1+2^2)+1/(2^2+3^2)+1/(3^2+4^2)+…+(2n+1)/n^2(n+1)^2
1个回答
相关问题
-
1.求Sn=2/2+3/2∧2+4/2∧3+...+n/2∧n-1+n+1/2∧n
-
求和:Sn=2/2+3/2^2+4/2^3+.+n/2^(n-1)+(n+1)/2^n
-
求和:Sn=2^/1*3+4^2/3*5+……(2n)^2/(2n-1)(2n+1)
-
Sn=(2^2+1)/(2^2-1)+(3^2+1)/(3^2-1)+…+(n^2+1)/(n^2-1)+[(n+1)^
-
sn=2*1/2+4*1/2^2+6*1/2^3+……+2n*1/2^n
-
Sn=(1+1)/2+(2+1)/2^2+(3+1)/2^3+``````+(n+1)/2^n=?
-
Sn=3/(1*2^2)+5/(2^2*3^2)+7/(3^2*4^2)+...+2n+1/[n^2(n+1)^2],求
-
Sn=1/(1^2+2)+1/(2^2+4)+1/(3^2+6)+...+1/(n^2+2n),求和
-
Sn=1/2!+2/3!+3/4!+.+n/(n+1)!
-
1.Sn=1*1/2+2*1/4+3*1/8+……+n/(1/2n)