你好,在吗?我想问下如果求两个数都同时递增然后相乘后再相加,应该用什么公式啊.

1个回答

  • 1*100+2*200+3*300+4*400+……+k*k*100

    =100(1²+2²+……+k²)

    =100*k(k+1)(2k+1)/6

    =50/3*k(k+1)(2k+1)

    n100+(n+1)200+(n+2)300+(n+3)400+……+(n+k-1)k*100

    =100[n*1+(n+1)*2+(n+2)*3+(n+3)*4+……+(n+k-1)*k*]

    = 100[(n-1+1)*1+(n-1+2)*2+(n-1+3)*3+(n-1+4)*4+……+(n-1+k)*k*]

    =100[(n-1)*1+1*1+(n-1)*2+2*2+(n-1)*3+3*3+……+(n-1)*k+k*k*]

    =100[(n-1)*(1+2+3+……+k)+1*1+*+2*2+3*3+……+k*k*]

    =100[(n-1)*k*(k+1)/2+k(k+1)(2k+1)/6]

    =50(n-1)*k*(k+1)+50/3*k(k+1)(2k+1)

    挺难的……希望LZ能看懂